Category: Hydrogen Atom

Enter the atomic number Z (2 to 6 or 0 to quit): 2
2       1       1       +       a(1)b(2)
1       0       0       -       a(2)b(1)
# Even Permutations = 1
Enter the atomic number Z (2 to 6 or 0 to quit): 3
6       3       1       +       a(1)b(2)c(3)
5       2       0       -       a(1)b(3)c(2)
4       2       0       -       a(2)b(1)c(3)
3       1       1       +       a(2)b(3)c(1)
2       1       1       +       a(3)b(1)c(2)
1       0       0       -       a(3)b(2)c(1)
# Even Permutations = 3
Enter the atomic number Z (2 to 6 or 0 to quit): 4
24      12      0       +       a(1)b(2)c(3)d(4)
23      11      1       -       a(1)b(2)c(4)d(3)
22      11      1       -       a(1)b(3)c(2)d(4)
21      10      0       +       a(1)b(3)c(4)d(2)
20      10      0       +       a(1)b(4)c(2)d(3)
19      9       1       -       a(1)b(4)c(3)d(2)
18      9       1       -       a(2)b(1)c(3)d(4)
17      8       0       +       a(2)b(1)c(4)d(3)
16      8       0       +       a(2)b(3)c(1)d(4)
15      7       1       -       a(2)b(3)c(4)d(1)
14      7       1       -       a(2)b(4)c(1)d(3)
13      6       0       +       a(2)b(4)c(3)d(1)
12      6       0       +       a(3)b(1)c(2)d(4)
11      5       1       -       a(3)b(1)c(4)d(2)
10      5       1       -       a(3)b(2)c(1)d(4)
9       4       0       +       a(3)b(2)c(4)d(1)
8       4       0       +       a(3)b(4)c(1)d(2)
7       3       1       -       a(3)b(4)c(2)d(1)
6       3       1       -       a(4)b(1)c(2)d(3)
5       2       0       +       a(4)b(1)c(3)d(2)
4       2       0       +       a(4)b(2)c(1)d(3)
3       1       1       -       a(4)b(2)c(3)d(1)
2       1       1       -       a(4)b(3)c(1)d(2)
1       0       0       +       a(4)b(3)c(2)d(1)
# Even Permutations = 12
Enter the atomic number Z (2 to 6 or 0 to quit):

// AOPermutations.cpp : This file contains the 'main' function.
// Program execution begins and ends there.
// Copyright (c) Saturday, March 29, 2025
// by James Pate Williams, Jr., BA, BS, MSwE, PhD
// Signs of the atomic orbitals in a Slater Determinant

#include <algorithm>
#include <iostream>
#include <string>
#include <vector>

int main()
{
    char alpha[] = { 'a', 'b', 'c', 'd', 'e', 'f' }, line[128] = {};
    int factorial[7] = { 1, 1, 2, 6, 24, 120, 720 };

    while (true)
    {
        int col = 0, counter = 0, row = 0, sign = 1, t = 0, Z = 0, zfact = 0;
        int numberEven = 0;
        std::cout << "Enter the atomic number Z (2 to 6 or 0 to quit): ";
        std::cin.getline(line, 127);
        std::string str(line);
        Z = std::stoi(str);

        if (Z == 0)
        {
            break;
        }

        if (Z < 2 || Z > 6)
        {
            std::cout << "Illegal Z, please try again" << std::endl;
            continue;
        }

        zfact = factorial[Z];

        std::vector<char> orb(Z);
        std::vector<int> tmp(Z), vec(Z);

        for (int i = 0; i < Z; i++)
        {
            orb[i] = alpha[i];
            vec[i] = i + 1;
        }

        do
        {
            for (int i = 0; i < (int)vec.size(); i++)
            {
                tmp[i] = vec[i];
            }

            t = 0;

            do
            {
                t++;
            } while (std::next_permutation(tmp.begin(), tmp.end()));

            std::cout << t << '\t' << t / 2 << '\t';
            std::cout << (t / 2 & 1) << '\t';

            if (Z == 2 || Z == 3)
            {
                if ((t / 2 & 1) == 0)
                {
                    std::cout << "-\t";
                }

                else
                {
                    std::cout << "+\t";
                    numberEven++;
                }
            }

            else
            {
                if ((t / 2 & 1) == 1)
                {
                    std::cout << "-\t";
                }

                else
                {
                    std::cout << "+\t";
                    numberEven++;
                }
            }

            for (int i = 0; i < Z; i++)
            {
                std::cout << orb[i] << '(' << vec[i] << ')';
            }

            row++;
            std::cout << std::endl;

            if (zfact != 2 && row == zfact)
            {
                std::cout << std::endl;
                break;
            }

            row %= Z;
        } while (std::next_permutation(vec.begin(), vec.end()));

        std::cout << "# Even Permutations = ";
        std::cout << numberEven << std::endl;
    }

    return 0;
}