Category: Numerical Analysis
Blog Entry (c) Saturday, September 28, 2024, by James Pate Williams, Jr. New Iowa Ballistics Table
I created the following fast battleship Iowa class ballistics table using a single coefficient of form with the value 0.531. The ballistic coefficient is 19.86229.
For comparison use the actual October 1941 Iowa class ballistics tables:
https://eugeneleeslover.com/USN-GUNS-AND-RANGE-TABLES/OP-770-1.html
Blog Entry © Thursday September 26, 2024, by James Pate Williams, Jr. Atmospheric Air Density Two Models
I wrote a C# program to graph NASA’s Earth Atmospheric Model’s variation of air density with height in Imperial Units and the United States Navy’s air density altitude equation.
Earth Atmosphere Model – Imperial Units (nasa.gov)
The USN’s formula for density – altitude is found in “Exterior ballistics, 1935” by Lieutenant Commander Ernest Edward Herrmann who was an instructor at the United States Naval Academy.


Blog Entry (c) Thursday September 19, 2024, by James Pate Williams, Jr. Ship to Ship Ballistics
The following graphs and data are for a hypothetical engagement between the Battleship Iowa (BB-61) and an unlucky enemy warship. My numbers are very close to those found in Ordnance Pamphlet 770 at the following website:
https://eugeneleeslover.com/USN-GUNS-AND-RANGE-TABLES/OP-770-1.html
Blog Entry (c) Monday September 16, 2024, by James Pate Williams, Jr. Variation of the Gravitational Acceleration on Earth with Height
Blog Entry (c) Saturday, September 14, 2024, The Mandelbrot Set by James Pate Williams, Jr. A Simple Fractal Self-Similar Curve

Blog Entry (c) Thursday, September 12, 2024, by James Pate Williams, Jr. Some Backpropagation Neural Network Results
Blog Entry (c) Monday September 2, 2024, by James Pate Williams, Jr. Corrected Online Integral Problem
Blog Entry (c) Sunday September 1, 2024, by James Pate Williams, Jr. An Online Integral Evaluation
Blog Entry (c) Saturday August 31, 2024, by James Pate Williams, Jr. An Elementary School Problem Found Online
Solve for a real root of the equation
f(x)=log6l(5+x)+log6l(x)=0
First we test our log6l(x) function
log6l(12) = 1.386853
log6l(36) = 2.000000
x = 0.1925824036
f = 0.0000000000