Category: Memoirs of James Pate Williams Jr
Blog Entry (c) Thursday, September 12, 2024, by James Pate Williams, Jr. Some Backpropagation Neural Network Results
Blog Entry (c) Tuesday September 3, 2024, by James Pate Williams, Jr.
Blog Entry (c) Monday September 2, 2024, by James Pate Williams, Jr. Corrected Online Integral Problem
Blog Entry (c) Sunday September 1, 2024, by James Pate Williams, Jr. An Online Integral Evaluation
Blog Entry (c) Saturday August 31, 2024, by James Pate Williams, Jr. Software Development About Two Decades Ago



Unfortunately, I can only find the preceding executable applications and no source code. These programs date back to 2001 and 2002 while I was a graduate student in software engineering and computer science at Auburn University. I seem to recall that these apps were created using Win32 C or C++.
Blog Entry (c) Saturday August 31, 2024, by James Pate Williams, Jr. An Elementary School Problem Found Online
Solve for a real root of the equation
f(x)=log6l(5+x)+log6l(x)=0
First we test our log6l(x) function
log6l(12) = 1.386853
log6l(36) = 2.000000
x = 0.1925824036
f = 0.0000000000
Blog Entry (c) Friday August 30, 2024, by James Pate Williams, Jr. Another Simple Math Problem
We use an evolutionary hill-climber and the solution of the quadratic equation to solve the easy problem below:
Solution of f(a,x)=sin(sqrt(ax-x^2))=0
Subject to the constraint x+y=100
Where x and y are the two roots of
g(a,x)=ax-x^2-n*n*pi*pi=0
and n=15
a = 100.347888933988
x = 32.947113268776
y = 67.400775665213
g = 0.000000000000
s = 100.347888933988
runtime in seconds = 43.730000
Blog Entry (c) Wednesday August 28, 2024, by James Pate Williams, Jr.
Blog Entry (c) Tuesday, August 27, 2024, Two More Online Mathematics Problems by James Pate Williams, Jr.
Solution of f(t) = cos(2t) + cos(3t)
t = 0.628318530718
f(t) = 1.11022302e-16
Solution of f(x) = sqrt(1 + sqrt(1 + x)) - x^1/3
x = 8.000000000000
f(x) = 0.00000000e+00
Solution of f(x) = 9^x + 12^x - 16^x
x = -16.387968065352
f(x) = 2.32137533e-16
Solution of f(x) = 8^x-2^x - 2(6^x-3^x)
x = 1.000000000000
f(x) = 0.00000000e+00