Category: Numerical Analysis
Blog Entry (c) Saturday, September 14, 2024, The Mandelbrot Set by James Pate Williams, Jr. A Simple Fractal Self-Similar Curve

Blog Entry (c) Thursday, September 12, 2024, by James Pate Williams, Jr. Some Backpropagation Neural Network Results
Blog Entry (c) Monday September 2, 2024, by James Pate Williams, Jr. Corrected Online Integral Problem
Blog Entry (c) Sunday September 1, 2024, by James Pate Williams, Jr. An Online Integral Evaluation
Blog Entry (c) Saturday August 31, 2024, by James Pate Williams, Jr. An Elementary School Problem Found Online
Solve for a real root of the equation
f(x)=log6l(5+x)+log6l(x)=0
First we test our log6l(x) function
log6l(12) = 1.386853
log6l(36) = 2.000000
x = 0.1925824036
f = 0.0000000000
Blog Entry (c) Friday August 30, 2024, by James Pate Williams, Jr. Another Simple Math Problem
We use an evolutionary hill-climber and the solution of the quadratic equation to solve the easy problem below:
Solution of f(a,x)=sin(sqrt(ax-x^2))=0
Subject to the constraint x+y=100
Where x and y are the two roots of
g(a,x)=ax-x^2-n*n*pi*pi=0
and n=15
a = 100.347888933988
x = 32.947113268776
y = 67.400775665213
g = 0.000000000000
s = 100.347888933988
runtime in seconds = 43.730000
Blog Entry (c) Wednesday August 28, 2024, by James Pate Williams, Jr.
Blog Entry (c) Tuesday, August 27, 2024, Two More Online Mathematics Problems by James Pate Williams, Jr.
Solution of f(t) = cos(2t) + cos(3t)
t = 0.628318530718
f(t) = 1.11022302e-16
Solution of f(x) = sqrt(1 + sqrt(1 + x)) - x^1/3
x = 8.000000000000
f(x) = 0.00000000e+00
Solution of f(x) = 9^x + 12^x - 16^x
x = -16.387968065352
f(x) = 2.32137533e-16
Solution of f(x) = 8^x-2^x - 2(6^x-3^x)
x = 1.000000000000
f(x) = 0.00000000e+00
Blog Entry August 9, 2024, (c) James Pate Williams, Jr. Another Online Math Problem
The problem is to find the real root of the equation: f(x)=x^(x^8)-8=0. I use the Newton-Raphson method, a root finding algorithm. A first guess is x = 2. The solution is: x = 1.2968395547, f(x) = -2.6645353e-15. I compute the necessary derivative using central-finite differences with a step size of h = 2/10000.