I wrote a short C++ program to calculate a few digits of pi, a famous transcendental number. The algorithms are as follows:
- Monte Carlo Method
- Leibniz’s Infinite Series
- Nilakantha’s Infinite Series
First the results then the C++ source code listing.



I wrote a short C++ program to calculate a few digits of pi, a famous transcendental number. The algorithms are as follows:
First the results then the C++ source code listing.







using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Windows.Forms;
namespace SteadyStateTempCylinder
{
public partial class MainForm : Form
{
private double steps;
private int N, nsteps;
private BackgroundWorker bw;
private DateTime dt0;
private List<PotPoint> pts;
private double f(double r)
{
return r;
}
private double g(double r)
{
return r * r;
}
public MainForm()
{
InitializeComponent();
comboBox1.SelectedIndex = 0;
comboBox2.SelectedIndex = 0;
comboBox3.SelectedIndex = 0;
}
private void button1_Click(object sender, EventArgs e)
{
if (button1.Text.CompareTo("&Draw") == 0)
{
N = int.Parse((string)comboBox1.SelectedItem);
nsteps = int.Parse((string)comboBox2.SelectedItem);
steps = double.Parse((string)comboBox3.SelectedItem);
bw = new BackgroundWorker();
bw.DoWork += new DoWorkEventHandler(bw_DoWork);
bw.ProgressChanged += new ProgressChangedEventHandler(bw_ProgressChanged);
bw.RunWorkerCompleted += new RunWorkerCompletedEventHandler(bw_RunWorkerCompleted);
bw.WorkerReportsProgress = true;
bw.WorkerSupportsCancellation = true;
bw.RunWorkerAsync();
while (!bw.IsBusy) { }
button1.Text = "&Stop";
textBox1.Text = string.Empty;
}
else
bw.CancelAsync();
}
private void bw_ProgressChanged(object sender, ProgressChangedEventArgs e)
{
if (e.ProgressPercentage >= 0 && e.ProgressPercentage <= 100)
progressBar1.Value = e.ProgressPercentage;
}
private void bw_RunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
try
{
DateTime dt1 = DateTime.Now;
TimeSpan ts = dt1 - dt0;
DrawGraphForm dgf = new DrawGraphForm(1.0, 1.0, pts);
dgf.Show();
button1.Text = "&Draw";
progressBar1.Value = 0;
textBox1.Text = ts.Hours.ToString("D2") + ":";
textBox1.Text += ts.Minutes.ToString("D2") + ":";
textBox1.Text += ts.Seconds.ToString("D2") + ".";
textBox1.Text += ts.Milliseconds.ToString("D3");
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString(), "Warning Message",
MessageBoxButtons.OK, MessageBoxIcon.Warning);
}
}
private void bw_DoWork(object sender, DoWorkEventArgs e)
{
dt0 = DateTime.Now;
double step = 1.0 / Math.Sqrt(steps);
double percent = steps / 100.0;
int total = 0;
int count = 0;
pts = new List<PotPoint>();
double r = 0.0, z = 0.0;
double umin = double.MaxValue;
double umax = double.MinValue;
SteadyStateTemp sst = new SteadyStateTemp(1.0, 1.0, N, nsteps, f, g);
while (r <= 1.0)
{
z = 0.0;
while (z <= 1.0)
{
double u = sst.u(r, z);
PotPoint pt = new PotPoint(r, z, u);
pts.Add(pt);
z += step;
count++;
if (count >= percent)
{
count = 0;
total++;
bw.ReportProgress(total);
}
if (u < umin)
umin = u;
if (u > umax)
umax = u;
}
r += step;
}
}
}
}
using System;
namespace SteadyStateTempCylinder
{
class SteadyStateTemp
{
private double A, B;
private double[] Jn;
private double[] lambda;
private int N, n, nsteps;
private BesselFunctions bf;
private Func<double, double> f;
Func<double, double> g;
public SteadyStateTemp(
double A,
double B,
int N, int nsteps,
Func<double, double> f,
Func<double, double> g)
{
double[] zeros = new double[N];
this.A = A;
this.B = B;
this.N = N;
this.nsteps = nsteps;
this.f = f;
this.g = g;
Jn = new double[N + 1];
lambda = new double[N + 1];
bf = new BesselFunctions();
bf.besszeros(1, N, zeros, 1);
for (n = 1; n <= N; n++)
{
lambda[n] = zeros[n - 1];
Jn[n] = J();
}
}
private double SimpsonsRule(double lower, double upper, Func<double, double> f)
{
double h = (upper - lower) / nsteps;
double h2 = 2.0 * h;
double s = 0.0;
double t = 0.0;
double x = lower + h;
for (int i = 1; i < nsteps; i += 2)
{
s += f(x);
x += h2;
}
x = lower + h2;
for (int i = 2; i < nsteps; i += 2)
{
t += f(x);
x += h2;
}
return h * (f(lower) + 4 * s + 2 * t + f(upper)) / 3.0;
}
private double IIntegrand(double r)
{
return bf.bessj0(lambda[n] * r) * r;
}
private double I()
{
return SimpsonsRule(0.0, A, IIntegrand);
}
private double JIntegrand(double r)
{
double b0 = bf.bessj0(lambda[n] * r);
return b0 * b0 * r;
}
private double J()
{
return SimpsonsRule(0.0, A, JIntegrand);
}
private double KIntegrand(double r)
{
return bf.bessj0(lambda[n] * r) * f(r) * r;
}
private double K()
{
return SimpsonsRule(0.0, A, KIntegrand);
}
private double LIntegrand(double r)
{
return bf.bessj0(lambda[n] * r) * g(r) * r;
}
private double L()
{
return SimpsonsRule(0.0, A, LIntegrand);
}
public double u(double r, double z)
{
double sum = 0.0;
for (n = 1; n <= N; n++)
{
double denom = Math.Sinh(lambda[n] * B);
double J0 = bf.bessj0(lambda[n] * r);
double an = L() / Jn[n];
double bn = K() / Jn[n];
sum += J0 * an * Math.Sinh(lambda[n] * z) / denom;
sum += J0 * bn * Math.Sinh(lambda[n] * (B - z)) / denom;
}
return sum;
}
}
}
using System;
namespace SteadyStateTempCylinder
{
class BesselFunctions
{
public double bessj0(double x)
{
if (x == 0.0) return 1.0;
if (Math.Abs(x) < 8.0)
{
int i;
double z, z2, b0, b1, b2;
double[] ar ={-0.75885e-15, 0.4125321e-13,
-0.194383469e-11, 0.7848696314e-10, -0.267925353056e-8,
0.7608163592419e-7, -0.176194690776215e-5,
0.324603288210051e-4, -0.46062616620628e-3,
0.48191800694676e-2, -0.34893769411409e-1,
0.158067102332097, -0.37009499387265, 0.265178613203337,
-0.872344235285222e-2};
x /= 8.0;
z = 2.0 * x * x - 1.0;
z2 = z + z;
b1 = b2 = 0.0;
for (i = 0; i <= 14; i++)
{
b0 = z2 * b1 - b2 + ar[i];
b2 = b1;
b1 = b0;
}
return z * b1 - b2 + 0.15772797147489;
}
else
{
double c, cosx, sinx, p0 = 0.0, q0 = 0.0;
x = Math.Abs(x);
c = 0.797884560802865 / Math.Sqrt(x);
cosx = Math.Cos(x - 0.706858347057703e1);
sinx = Math.Sin(x - 0.706858347057703e1);
besspq0(x, ref p0, ref q0);
return c * (p0 * cosx - q0 * sinx);
}
}
public double bessj1(double x)
{
if (x == 0.0) return 1.0;
if (Math.Abs(x) < 8.0)
{
int i;
double z, z2, b0, b1, b2;
double[] ar ={-0.19554e-15, 0.1138572e-13,
-0.57774042e-12, 0.2528123664e-10, -0.94242129816e-9,
0.2949707007278e-7, -0.76175878054003e-6,
0.158870192399321e-4, -0.260444389348581e-3,
0.324027018268386e-2, -0.291755248061542e-1,
0.177709117239728e0, -0.661443934134543e0,
0.128799409885768e1, -0.119180116054122e1};
x /= 8.0;
z = 2.0 * x * x - 1.0;
z2 = z + z;
b1 = b2 = 0.0;
for (i = 0; i <= 14; i++)
{
b0 = z2 * b1 - b2 + ar[i];
b2 = b1;
b1 = b0;
}
return x * (z * b1 - b2 + 0.648358770605265);
}
else
{
int sgnx;
double c, cosx, sinx, p1 = 0.0, q1 = 0.0;
sgnx = (x > 0.0) ? 1 : -1;
x = Math.Abs(x);
c = 0.797884560802865 / Math.Sqrt(x);
cosx = Math.Cos(x - 0.706858347057703e1);
sinx = Math.Sin(x - 0.706858347057703e1);
besspq1(x, ref p1, ref q1);
return sgnx * c * (p1 * sinx + q1 * cosx);
}
}
private void besspq0(double x, ref double p0, ref double q0)
{
if (x < 8.0)
{
double b, cosx, sinx, j0x = 0.0, y0 = 0.0;
b = Math.Sqrt(x) * 1.25331413731550;
bessy01(x, ref y0, ref j0x);
j0x = bessj0(x);
x -= 0.785398163397448;
cosx = Math.Cos(x);
sinx = Math.Sin(x);
p0 = b * (y0 * sinx + j0x * cosx);
q0 = b * (y0 * cosx - j0x * sinx);
}
else
{
int i;
double x2, b0, b1, b2, y;
double[] ar1 ={-0.10012e-15, 0.67481e-15, -0.506903e-14,
0.4326596e-13, -0.43045789e-12, 0.516826239e-11,
-0.7864091377e-10, 0.163064646352e-8, -0.5170594537606e-7,
0.30751847875195e-5, -0.536522046813212e-3};
double[] ar2 ={-0.60999e-15, 0.425523e-14,
-0.3336328e-13, 0.30061451e-12, -0.320674742e-11,
0.4220121905e-10, -0.72719159369e-9, 0.1797245724797e-7,
-0.74144984110606e-6, 0.683851994261165e-4};
y = 8.0 / x;
x = 2.0 * y * y - 1.0;
x2 = x + x;
b1 = b2 = 0.0;
for (i = 0; i <= 10; i++)
{
b0 = x2 * b1 - b2 + ar1[i];
b2 = b1;
b1 = b0;
}
p0 = x * b1 - b2 + 0.99946034934752;
b1 = b2 = 0.0;
for (i = 0; i <= 9; i++)
{
b0 = x2 * b1 - b2 + ar2[i];
b2 = b1;
b1 = b0;
}
q0 = (x * b1 - b2 - 0.015555854605337) * y;
}
}
private void besspq1(double x, ref double p1, ref double q1)
{
if (x < 8.0)
{
double b, cosx, sinx, j1x = 0.0, y1 = 0.0;
b = Math.Sqrt(x) * 1.25331413731550;
bessy01(x, ref j1x, ref y1);
j1x = bessj1(x);
x -= 0.785398163397448;
cosx = Math.Cos(x);
sinx = Math.Sin(x);
p1 = b * (j1x * sinx - y1 * cosx);
q1 = b * (j1x * cosx + y1 * sinx);
}
else
{
int i;
double x2, b0, b1, b2, y;
double[] ar1 ={0.10668e-15, -0.72212e-15, 0.545267e-14,
-0.4684224e-13, 0.46991955e-12, -0.570486364e-11,
0.881689866e-10, -0.187189074911e-8, 0.6177633960644e-7,
-0.39872843004889e-5, 0.89898983308594e-3};
double[] ar2 ={-0.10269e-15, 0.65083e-15, -0.456125e-14,
0.3596777e-13, -0.32643157e-12, 0.351521879e-11,
-0.4686363688e-10, 0.82291933277e-9, -0.2095978138408e-7,
0.91386152579555e-6, -0.96277235491571e-4};
y = 8.0 / x;
x = 2.0 * y * y - 1.0;
x2 = x + x;
b1 = b2 = 0.0;
for (i = 0; i <= 10; i++)
{
b0 = x2 * b1 - b2 + ar1[i];
b2 = b1;
b1 = b0;
}
p1 = x * b1 - b2 + 1.0009030408600137;
b1 = b2 = 0.0;
for (i = 0; i <= 10; i++)
{
b0 = x2 * b1 - b2 + ar2[i];
b2 = b1;
b1 = b0;
}
q1 = (x * b1 - b2 + 0.46777787069535e-1) * y;
}
}
private void bessy01(double x, ref double y0, ref double y1)
{
if (x < 8.0)
{
int i;
double z, z2, c, lnx, b0, b1, b2;
double[] ar1 ={0.164349e-14, -0.8747341e-13,
0.402633082e-11, -0.15837552542e-9, 0.524879478733e-8,
-0.14407233274019e-6, 0.32065325376548e-5,
-0.563207914105699e-4, 0.753113593257774e-3,
-0.72879624795521e-2, 0.471966895957634e-1,
-0.177302012781143, 0.261567346255047,
0.179034314077182, -0.274474305529745};
double[] ar2 ={0.42773e-15, -0.2440949e-13,
0.121143321e-11, -0.5172121473e-10, 0.187547032473e-8,
-0.5688440039919e-7, 0.141662436449235e-5,
-0.283046401495148e-4, 0.440478629867099e-3,
-0.51316411610611e-2, 0.423191803533369e-1,
-0.226624991556755, 0.675615780772188,
-0.767296362886646, -0.128697384381350};
c = 0.636619772367581;
lnx = c * Math.Log(x);
c /= x;
x /= 8.0;
z = 2.0 * x * x - 1.0;
z2 = z + z;
b1 = b2 = 0.0;
for (i = 0; i <= 14; i++)
{
b0 = z2 * b1 - b2 + ar1[i];
b2 = b1;
b1 = b0;
}
y0 = lnx * bessj0(8.0 * x) + z * b1 - b2 - 0.33146113203285e-1;
b1 = b2 = 0.0;
for (i = 0; i <= 14; i++)
{
b0 = z2 * b1 - b2 + ar2[i];
b2 = b1;
b1 = b0;
}
y1 = lnx * bessj1(8.0 * x) - c + x * (z * b1 - b2 + 0.2030410588593425e-1);
}
else
{
double c, cosx, sinx, p0 = 0.0, q0 = 0.0, p1 = 0.0, q1 = 0.0;
c = 0.797884560802865 / Math.Sqrt(x);
besspq0(x, ref p0, ref q0);
besspq1(x, ref p1, ref q1);
x -= 0.706858347057703e1;
cosx = Math.Cos(x);
sinx = Math.Sin(x);
y0 = c * (p0 * sinx + q0 * cosx);
y1 = c * (q1 * sinx - p1 * cosx);
}
}
private double recipgamma(double x, ref double odd, ref double even)
{
int i;
double alfa, beta, x2;
double[] b = new double[13];
b[1] = -0.283876542276024; b[2] = -0.076852840844786;
b[3] = 0.001706305071096; b[4] = 0.001271927136655;
b[5] = 0.000076309597586; b[6] = -0.000004971736704;
b[7] = -0.000000865920800; b[8] = -0.000000033126120;
b[9] = 0.000000001745136; b[10] = 0.000000000242310;
b[11] = 0.000000000009161; b[12] = -0.000000000000170;
x2 = x * x * 8.0;
alfa = -0.000000000000001;
beta = 0.0;
for (i = 12; i >= 2; i -= 2)
{
beta = -(alfa * 2.0 + beta);
alfa = -beta * x2 - alfa + b[i];
}
even = (beta / 2.0 + alfa) * x2 - alfa + 0.921870293650453;
alfa = -0.000000000000034;
beta = 0.0;
for (i = 11; i >= 1; i -= 2)
{
beta = -(alfa * 2.0 + beta);
alfa = -beta * x2 - alfa + b[i];
}
odd = (alfa + beta) * 2.0;
return odd * x + even;
}
private void bessya01(double a, double x, ref double ya, ref double ya1)
{
if (a == 0.0)
{
bessy01(x, ref ya, ref ya1);
}
else
{
bool rec, rev;
int n, na;
double b, c, d, e, f, g, h = 0.0, p = 0.0, pi, q = 0.0, r, s;
pi = Math.PI;
na = (int)Math.Floor(a + 0.5);
rec = (a >= 0.5);
rev = (a < -0.5);
if (rev || rec) a -= na;
if (a == -0.5)
{
p = Math.Sqrt(2.0 / pi / x);
f = p * Math.Sin(x);
g = -p * Math.Cos(x);
}
else if (x < 3.0)
{
b = x / 2.0;
d = -Math.Log(b);
e = a * d;
c = (Math.Abs(a) < 1.0e-8) ? 1.0 / pi : a / Math.Sin(a * pi);
s = (Math.Abs(e) < 1.0e-8) ? 1.0 : Math.Sinh(e) / e;
e = Math.Exp(e);
g = recipgamma(a, ref p, ref q) * e;
e = (e + 1.0 / e) / 2.0;
f = 2.0 * c * (p * e + q * s * d);
e = a * a;
p = g * c;
q = 1.0 / g / pi;
c = a * pi / 2.0;
r = (Math.Abs(c) < 1.0e-8) ? 1.0 : Math.Sin(c) / c;
r *= pi * c * r;
c = 1.0;
d = -b * b;
ya = f + r * q;
ya1 = p;
n = 1;
do
{
f = (f * n + p + q) / (n * n - e);
c = c * d / n;
p /= (n - a);
q /= (n + a);
g = c * (f + r * q);
h = c * p - n * g;
ya += g;
ya1 += h;
n++;
} while (Math.Abs(g / (1.0 + Math.Abs(ya))) + Math.Abs(h / (1.0 + Math.Abs(ya1))) >
1.0e-15);
f = -ya;
g = -ya1 / b;
}
else
{
b = x - pi * (a + 0.5) / 2.0;
c = Math.Cos(b);
s = Math.Sin(b);
d = Math.Sqrt(2.0 / x / pi);
besspqa01(a, x, ref p, ref q, ref b, ref h);
f = d * (p * s + q * c);
g = d * (h * s - b * c);
}
if (rev)
{
x = 2.0 / x;
na = -na - 1;
for (n = 0; n <= na; n++)
{
h = x * (a - n) * f - g;
g = f;
f = h;
}
}
else if (rec)
{
x = 2.0 / x;
for (n = 1; n <= na; n++)
{
h = x * (a + n) * g - f;
f = g;
g = h;
}
}
ya = f;
ya1 = g;
}
}
private int start(double x, int n, int t)
{
int s;
double p, q, r, y;
s = 2 * t - 1;
p = 36.0 / x - t;
r = n / x;
if (r > 1.0 || t == 1)
{
q = Math.Sqrt(r * r + s);
r = r * Math.Log(q + r) - q;
}
else
r = 0.0;
q = 18.0 / x + r;
r = (p > q) ? p : q;
p = Math.Sqrt(2.0 * (t + r));
p = x * ((1.0 + r) + p) / (1.0 + p);
y = 0.0;
q = y;
do
{
y = p;
p /= x;
q = Math.Sqrt(p * p + s);
p = x * (r + q) / Math.Log(p + q);
q = y;
} while (p > q || p < q - 1.0);
return (t == 1) ? (int)Math.Floor(p + 1.0) : -(int)Math.Floor(-p / 2.0) * 2;
}
public void bessj(double x, int n, double[] j)
{
if (x == 0.0)
{
j[0] = 1.0;
for (; n >= 1; n--) j[n] = 0.0;
}
else
{
int l, m, nu, signx;
double x2, r, s;
signx = (x > 0.0) ? 1 : -1;
x = Math.Abs(x);
r = s = 0.0;
x2 = 2.0 / x;
l = 0;
nu = start(x, n, 0);
for (m = nu; m >= 1; m--)
{
r = 1.0 / (x2 * m - r);
l = 2 - l;
s = r * (l + s);
if (m <= n) j[m] = r;
}
j[0] = r = 1.0 / (1.0 + s);
for (m = 1; m <= n; m++) r = j[m] *= r;
if (signx < 0.0)
for (m = 1; m <= n; m += 2) j[m] = -j[m];
}
}
private void spherbessj(double x, int n, double[] j)
{
if (x == 0.0)
{
j[0] = 1.0;
for (; n >= 1; n--) j[n] = 0.0;
}
else if (n == 0)
{
double x2;
if (Math.Abs(x) < 0.015)
{
x2 = x * x / 6.0;
j[0] = 1.0 + x2 * (x2 * 0.3 - 1.0);
}
else
j[0] = Math.Sin(x) / x;
}
else
{
int m;
double r, s;
r = 0.0;
m = start(x, n, 0);
for (; m >= 1; m--)
{
r = 1.0 / ((m + m + 1) / x - r);
if (m <= n) j[m] = r;
}
if (x < 0.015)
{
s = x * x / 6.0;
j[0] = r = s * (s * 0.3 - 1.0) + 1.0;
}
else
j[0] = r = Math.Sin(x) / x;
for (m = 1; m <= n; m++) r = j[m] *= r;
}
}
private double loggamma(double x)
{
int i;
double r, x2, y, f, u0, u1, u, z;
double[] b = new double[19];
if (x > 13.0)
{
r = 1.0;
while (x <= 22.0)
{
r /= x;
x += 1.0;
}
x2 = -1.0 / (x * x);
r = Math.Log(r);
return Math.Log(x) * (x - 0.5) - x + r + 0.918938533204672 +
(((0.595238095238095e-3 * x2 + 0.793650793650794e-3) * x2 +
0.277777777777778e-2) * x2 + 0.833333333333333e-1) / x;
}
else
{
f = 1.0;
u0 = u1 = 0.0;
b[1] = -0.0761141616704358; b[2] = 0.0084323249659328;
b[3] = -0.0010794937263286; b[4] = 0.0001490074800369;
b[5] = -0.0000215123998886; b[6] = 0.0000031979329861;
b[7] = -0.0000004851693012; b[8] = 0.0000000747148782;
b[9] = -0.0000000116382967; b[10] = 0.0000000018294004;
b[11] = -0.0000000002896918; b[12] = 0.0000000000461570;
b[13] = -0.0000000000073928; b[14] = 0.0000000000011894;
b[15] = -0.0000000000001921; b[16] = 0.0000000000000311;
b[17] = -0.0000000000000051; b[18] = 0.0000000000000008;
if (x < 1.0)
{
f = 1.0 / x;
x += 1.0;
}
else
while (x > 2.0)
{
x -= 1.0;
f *= x;
}
f = Math.Log(f);
y = x + x - 3.0;
z = y + y;
for (i = 18; i >= 1; i--)
{
u = u0;
u0 = z * u0 + b[i] - u1;
u1 = u;
}
return (u0 * y + 0.491415393029387 - u1) * (x - 1.0) * (x - 2.0) + f;
}
}
private double gamma(double x)
{
int inv;
double y, s, f = 0.0, g, odd = 0.0, even = 0.0;
if (x < 0.5)
{
y = x - Math.Floor(x / 2.0) * 2;
s = Math.PI;
if (y >= 1.0)
{
s = -s;
y = 2.0 - y;
}
if (y >= 0.5) y = 1.0 - y;
inv = 1;
x = 1.0 - x;
f = s / Math.Sin(3.14159265358979 * y);
}
else
inv = 0;
if (x > 22.0)
g = Math.Exp(loggamma(x));
else
{
s = 1.0;
while (x > 1.5)
{
x = x - 1.0;
s *= x;
}
g = s / recipgamma(1.0 - x, ref odd, ref even);
}
return (inv == 1 ? f / g : g);
}
private void bessjaplusn(double a, double x, int n, double[] ja)
{
if (x == 0.0)
{
ja[0] = (a == 0.0) ? 1.0 : 0.0;
for (; n >= 1; n--) ja[n] = 0.0;
}
else if (a == 0.0)
{
bessj(x, n, ja);
}
else if (a == 0.5)
{
double s;
s = Math.Sqrt(x) * 0.797884560802865;
spherbessj(x, n, ja);
for (; n >= 0; n--) ja[n] *= s;
}
else
{
int k, m, nu;
double a2, x2, r, s, l, labda;
l = 1.0;
nu = start(x, n, 0);
for (m = 1; m <= nu; m++) l = l * (m + a) / (m + 1);
r = s = 0.0;
x2 = 2.0 / x;
k = -1;
a2 = a + a;
for (m = nu + nu; m >= 1; m--)
{
r = 1.0 / (x2 * (a + m) - r);
if (k == 1)
labda = 0.0;
else
{
l = l * (m + 2) / (m + a2);
labda = l * (m + a);
}
s = r * (labda + s);
k = -k;
if (m <= n) ja[m] = r;
}
ja[0] = r = 1.0 / gamma(1.0 + a) / (1.0 + s) / Math.Pow(x2, a);
for (m = 1; m <= n; m++) r = ja[m] *= r;
}
}
private void besspqa01(double a, double x, ref double pa, ref double qa,
ref double pa1, ref double qa1)
{
if (a == 0.0)
{
besspq0(x, ref pa, ref qa);
besspq1(x, ref pa1, ref qa1);
}
else
{
bool rec, rev;
int n, na = 0;
double b, pi, p0, q0;
pi = Math.PI;
rev = a < -0.5;
if (rev) a = -a - 1.0;
rec = a >= 0.5;
if (rec)
{
na = (int)Math.Floor(a + 0.5);
a -= na;
}
if (a == -0.5)
{
pa = pa1 = 1.0;
qa = qa1 = 0.0;
}
else if (x >= 3.0)
{
double c, d, e, f, g, p, q, r, s, temp;
c = 0.25 - a * a;
b = x + x;
f = r = 1.0;
g = -x;
s = 0.0;
temp = x * Math.Cos(a * pi) / pi * 1.0e15;
e = temp * temp;
n = 2;
do
{
d = (n - 1 + c / n);
p = (2 * n * f + b * g - d * r) / (n + 1);
q = (2 * n * g - b * f - d * s) / (n + 1);
r = f;
f = p;
s = g;
g = q;
n++;
} while ((p * p + q * q) * n * n < e);
e = f * f + g * g;
p = (r * f + s * g) / e;
q = (s * f - r * g) / e;
f = p;
g = q;
n--;
while (n > 0)
{
r = (n + 1) * (2.0 - p) - 2.0;
s = b + (n + 1) * q;
d = (n - 1 + c / n) / (r * r + s * s);
p = d * r;
q = d * s;
e = f;
f = p * (e + 1.0) - g * q;
g = q * (e + 1.0) + p * g;
n--;
}
f += 1.0;
d = f * f + g * g;
pa = f / d;
qa = -g / d;
d = a + 0.5 - p;
q += x;
pa1 = (pa * q - qa * d) / x;
qa1 = (qa * q + pa * d) / x;
}
else
{
double c, s, chi, ya = 0.0, ya1 = 0.0;
double[] ja = new double[2];
b = Math.Sqrt(pi * x / 2.0);
chi = x - pi * (a / 2.0 + 0.25);
c = Math.Cos(chi);
s = Math.Sin(chi);
bessya01(a, x, ref ya, ref ya1);
bessjaplusn(a, x, 1, ja);
pa = b * (ya * s + c * ja[0]);
qa = b * (c * ya - s * ja[0]);
pa1 = b * (s * ja[1] - c * ya1);
qa1 = b * (c * ja[1] + s * ya1);
}
if (rec)
{
x = 2.0 / x;
b = (a + 1.0) * x;
for (n = 1; n <= na; n++)
{
p0 = pa - qa1 * b;
q0 = qa + pa1 * b;
pa = pa1;
pa1 = p0;
qa = qa1;
qa1 = q0;
b += x;
}
}
if (rev)
{
p0 = pa1;
pa1 = pa;
pa = p0;
q0 = qa1;
qa1 = qa;
qa = q0;
}
}
}
public void besszeros(double a, int n, double[] z, int d)
{
int j, s;
double aa, a2, b, bb, c, chi, co, mu, mu2, mu3, mu4, p, pi, pa = 0.0, pa1 = 0.0, p0, p1, pp1,
q, qa = 0.0, qa1 = 0.0, q1, qq1, ro, si, t, tt, u, v, w, x, xx, x4, y, yy, fi;
pi = Math.PI;
aa = a * a;
mu = 4.0 * aa;
mu2 = mu * mu;
mu3 = mu * mu2;
mu4 = mu2 * mu2;
if (d < 3)
{
p = 7.0 * mu - 31.0;
p0 = mu - 1.0;
p1 = 4.0 * (253.0 * mu2 - 3722.0 * mu + 17869.0) / 15.0 / p * p0;
q1 = 8.0 * (83.0 * mu2 - 982.0 * mu + 3779.0) / 5.0 / p;
}
else
{
p = 7.0 * mu2 + 82.0 * mu - 9.0;
p0 = mu + 3.0;
p1 = (4048.0 * mu4 + 131264.0 * mu3 - 221984.0 * mu2 -
417600.0 * mu + 1012176.0) / 60.0 / p;
q1 = 1.6 * (83.0 * mu3 + 2075.0 * mu2 - 3039.0 * mu + 3537.0) / p;
}
t = (d == 1 || d == 4) ? 0.25 : 0.75;
tt = 4.0 * t;
if (d < 3)
{
pp1 = 5.0 / 48.0;
qq1 = -5.0 / 36.0;
}
else
{
pp1 = -7.0 / 48.0;
qq1 = 35.0 / 288.0;
}
y = 3.0 * pi / 8.0;
bb = (a >= 3.0) ? Math.Pow(a, -2.0 / 3.0) : 0.0;
for (s = 1; s <= n; s++)
{
if (a == 0.0 && s == 1 && d == 3)
{
x = 0.0;
j = 0;
}
else
{
if (s >= 3.0 * a - 8.0)
{
b = (s + a / 2.0 - t) * pi;
c = 1.0 / b / b / 64.0;
x = b - 1.0 / b / 8.0 * (p0 - p1 * c) / (1.0 - q1 * c);
}
else
{
if (s == 1)
x = ((d == 1) ? -2.33811 : ((d == 2) ? -1.17371 :
((d == 3) ? -1.01879 : -2.29444)));
else
{
x = y * (4.0 * s - tt);
v = 1.0 / x / x;
x = -Math.Pow(x, 2.0 / 3.0) * (1.0 + v * (pp1 + qq1 * v));
}
u = x * bb;
yy = 2.0 / 3.0 * Math.Pow(-u, 1.5);
if (yy == 0.0)
fi = 0.0;
else if (yy > 1.0e5)
fi = 1.570796;
else
{
double r, pp;
if (yy < 1.0)
{
p = Math.Pow(3.0 * yy, 1.0 / 3.0);
pp = p * p;
p *= (1.0 + pp * (-210.0 + pp * (27.0 - 2.0 * pp)) / 1575.0);
}
else
{
p = 1.0 / (yy + 1.570796);
pp = p * p;
p = 1.570796 - p * (1.0 + pp * (2310.0 + pp * (3003.0 + pp *
(4818.0 + pp * (8591.0 + pp * 16328.0)))) / 3465.0);
}
pp = (yy + p) * (yy + p);
r = (p - Math.Atan(p + yy)) / pp;
fi = p - (1.0 + pp) * r * (1.0 + r / (p + yy));
}
v = fi;
w = 1.0 / Math.Cos(v);
xx = 1.0 - w * w;
c = Math.Sqrt(u / xx);
x = w * (a + c / a / u * ((d < 3) ?
-5.0 / 48.0 / u - c * (-5.0 / 24.0 / xx + 1.0 / 8.0) :
7.0 / 48.0 / u + c * (-7.0 / 24.0 / xx + 3.0 / 8.0)));
}
j = 0;
do
{
xx = x * x;
x4 = xx * xx;
a2 = aa - xx;
besspqa01(a, x, ref pa, ref qa, ref pa1, ref qa1);
chi = x - pi * (a / 2.0 + 0.25);
si = Math.Sin(chi);
co = Math.Cos(chi);
ro = ((d == 1) ? (pa * co - qa * si) / (pa1 * si + qa1 * co) :
((d == 2) ? (pa * si + qa * co) / (qa1 * si - pa1 * co) :
((d == 3) ? a / x - (pa1 * si + qa1 * co) / (pa * co - qa * si) :
a / x - (qa1 * si - pa1 * co) / (pa * si + qa * co))));
j++;
if (d < 3)
{
u = ro;
p = (1.0 - 4.0 * a2) / 6.0 / x / (2.0 * a + 1.0);
q = (2.0 * (xx - mu) - 1.0 - 6.0 * a) / 3.0 / x / (2.0 * a + 1.0);
}
else
{
u = -xx * ro / a2;
v = 2.0 * x * a2 / (aa + xx) / 3.0;
w = a2 * a2 * a2;
q = v * (1.0 + (mu2 + 32.0 * mu * xx + 48.0 * x4) / 32.0 / w);
p = v * (1.0 + (-mu2 + 40.0 * mu * xx + 48.0 * x4) / 64.0 / w);
}
w = u * (1.0 + p * ro) / (1.0 + q * ro);
x += w;
} while (Math.Abs(w / x) > 1.0e-13 && j < 5);
}
z[s - 1] = x;
}
}
}
}
using System;
using System.Collections.Generic;
using System.Drawing;
using System.Windows.Forms;
namespace SteadyStateTempCylinder
{
public partial class DrawGraphForm : Form
{
private const double epsilon = 1.0e-2;
private double xMax;
private double yMax;
private int n;
private Brush brush;
private Brush potBrush;
private Font font;
private Pen pen1, pen2;
private List<PotPoint> pts;
public DrawGraphForm(
double xMax,
double yMax,
List<PotPoint> pts)
{
InitializeComponent();
this.xMax = xMax;
this.yMax = yMax;
this.pts = pts;
n = pts.Count;
brush = new SolidBrush(Color.Black);
potBrush = new SolidBrush(Color.Red);
pen1 = new Pen(Color.Black);
pen2 = new Pen(Color.Blue);
font = new Font("Courier New", 12f, FontStyle.Bold);
panel1.Paint += new PaintEventHandler(PanelPaintHandler);
}
private void DrawGraph(float u0, float v0,
float u1, float v1,
Graphics g)
{
try
{
float xMin = u0;
float yMin = v0;
float xMax = u1;
float yMax = v1;
float xSpan = xMax - xMin;
float ySpan = yMax - yMin;
float deltaX = xSpan / 8.0f;
float deltaY = ySpan / 8.0f;
float height = panel1.Height;
float width = panel1.Width;
float sx0 = 2f * width / 16f;
float sx1 = 14f * width / 16f;
float sy0 = 2f * height / 16f;
float sy1 = 14f * height / 16f;
float xSlope = (sx1 - sx0) / xSpan;
float xInter = sx0 - xSlope * xMin;
float ySlope = (sy0 - sy1) / ySpan;
float yInter = sy0 - ySlope * yMax;
float x = xMin;
float y = yMin;
string fTitle = "Graph of Constant u";
float w = g.MeasureString(fTitle, font).Width;
float h = g.MeasureString(fTitle, font).Height;
g.DrawString(fTitle, font, brush,
(width - w) / 2f, h);
string xTitle = "r";
w = g.MeasureString(xTitle, font).Width;
g.DrawString(xTitle, font, brush,
sx0 + (sx1 - sx0 - w) / 2f, sy1 + h + h);
string yTitle = "z";
w = g.MeasureString(yTitle, font).Width;
g.DrawString(yTitle, font, brush,
sx1 + w / 5f, sy0 + (sy1 - sy0) / 2f - h / 2f);
int i = 0;
while (i <= 8)
{
float sx = xSlope * x + xInter;
string s = string.Format("{0,5:0.00}", x);
g.DrawLine(pen1, sx, sy0, sx, sy1);
w = g.MeasureString(s, font).Width;
g.DrawString(s, font, brush,
sx - w / 2, sy1 + h / 2f);
x += deltaX;
i++;
}
i = 0;
while (i <= 8)
{
float sy = ySlope * y + yInter;
string s = string.Format("{0,5:0.00}", y);
w = g.MeasureString(s, font).Width;
g.DrawLine(pen1, sx0, sy, sx1, sy);
g.DrawString(s, font, brush,
sx0 - w - w / 5f, sy - h / 2f);
y += deltaY;
i++;
}
g.Clip = new Region(new RectangleF(
sx0, sy0, (sx1 - sx0), (sy1 - sy0)));
for (i = 0; i < n; i++)
{
float px = (float)pts[i].X;
float py = (float)pts[i].Y;
float pu = (float)pts[i].U;
if (Math.Abs(pu + 0.05) < epsilon ||
Math.Abs(pu + 0.10) < epsilon ||
Math.Abs(pu + 0.15) < epsilon ||
Math.Abs(pu + 0.20) < epsilon ||
Math.Abs(pu + 0.25) < epsilon ||
Math.Abs(pu + 0.30) < epsilon ||
Math.Abs(pu + 0.35) < epsilon ||
Math.Abs(pu + 0.40) < epsilon ||
Math.Abs(pu + 0.45) < epsilon ||
Math.Abs(pu + 0.50) < epsilon ||
Math.Abs(pu + 0.55) < epsilon ||
Math.Abs(pu + 0.60) < epsilon ||
Math.Abs(pu + 0.55) < epsilon ||
Math.Abs(pu + 0.70) < epsilon ||
Math.Abs(pu + 0.75) < epsilon ||
Math.Abs(pu + 0.80) < epsilon ||
Math.Abs(pu + 0.85) < epsilon ||
Math.Abs(pu + 0.90) < epsilon ||
Math.Abs(pu + 0.95) < epsilon ||
Math.Abs(pu - 0.05) < epsilon ||
Math.Abs(pu - 0.10) < epsilon ||
Math.Abs(pu - 0.15) < epsilon ||
Math.Abs(pu - 0.20) < epsilon ||
Math.Abs(pu - 0.25) < epsilon ||
Math.Abs(pu - 0.30) < epsilon ||
Math.Abs(pu - 0.35) < epsilon ||
Math.Abs(pu - 0.40) < epsilon ||
Math.Abs(pu - 0.45) < epsilon ||
Math.Abs(pu - 0.50) < epsilon ||
Math.Abs(pu - 0.55) < epsilon ||
Math.Abs(pu - 0.60) < epsilon ||
Math.Abs(pu - 0.55) < epsilon ||
Math.Abs(pu - 0.70) < epsilon ||
Math.Abs(pu - 0.75) < epsilon ||
Math.Abs(pu - 0.80) < epsilon ||
Math.Abs(pu - 0.85) < epsilon ||
Math.Abs(pu - 0.90) < epsilon ||
Math.Abs(pu - 0.95) < epsilon)
{
float sx = xSlope * px + xInter;
float sy = ySlope * py + yInter;
g.FillEllipse(potBrush, (float)sx, (float)sy, 2.0f, 2.0f);
}
}
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString(), "Warning Message",
MessageBoxButtons.OK, MessageBoxIcon.Warning);
}
}
private void LayOutTheForm()
{
// layout the panel
int w = ClientSize.Width;
int h = ClientSize.Height;
panel1.Width = w;
panel1.Height = h;
panel1.Location = new Point(0, 0);
panel1.Invalidate();
}
protected void PanelPaintHandler(object sender, PaintEventArgs pa)
{
DrawGraph((float)0.0, (float)0.0, (float)xMax, (float)yMax, pa.Graphics);
}
protected override void OnResize(EventArgs ea)
{
LayOutTheForm();
}
}
}
using System;
namespace SteadyStateTempCylinder
{
public class PotPoint : IComparable
{
private double x, y, u;
public double X
{
get
{
return x;
}
set
{
x = value;
}
}
public double Y
{
get
{
return y;
}
set
{
y = value;
}
}
public double U
{
get
{
return u;
}
set
{
u = value;
}
}
public PotPoint(double x, double y, double u)
{
this.x = x;
this.y = y;
this.u = u;
}
public int CompareTo(object obj)
{
if (obj == null)
return 1;
PotPoint pp = (PotPoint)obj;
if (u > pp.u)
return 1;
else if (u == pp.u)
return 0;
else
return -1;
}
}
}
A simple number theoretic problem is to count and enumerate the number of divisors of a natural number which is the set { 1, 2, 3, … }. An Order(n) method is to find all numbers between 1 and n such that the number divides n. If you have the prime factorization of n then the number of divisors is the product of the prime factorization (exponents + 1). For example the divisors of 100 are:
1 2 4 5 10 20 25 50 100
The prime factorization of 100 = 2^2 * 5 ^ 2. So the number of divisors is (2 + 1) * (2 + 1) = 9.
Below is a C++ implementation of an algorithm to enumerate and count the number of divisors of a natural number and count the divisors by using the factorization found by trial division.
#include <algorithm>
#include <chrono>
#include <iostream>
#include <vector>
using namespace std;
const int B0 = 10000000;
bool sieve[B0 + 1];
vector<int> prime, divisors, expon, primes, primesSquares;
void Sieve()
{
// Sieve of Eratosthenes
// find all prime numbers
// less than or equal B0
int c = 3, i, inc;
sieve[2] = true;
for (i = 3; i <= B0; i++)
if (i % 2 == 1)
sieve[i] = true;
do
{
i = c * c;
inc = c + c;
while (i <= B0)
{
sieve[i] = false;
i += inc;
}
c += 2;
while (!sieve[c])
c++;
} while (c * c <= B0);
for (i = 2; i <= B0; i++)
{
if (sieve[i])
{
primes.push_back(i);
primesSquares.push_back(i * i);
}
}
}
bool TrialDivision(int number)
{
int bound = B0; // (int)sqrt(number);
for (int i = 0; i < (int)primes.size(); i++)
{
int p = primes[i];
if (p <= bound)
{
if (number % p == 0)
{
int e = 0;
while (number % p == 0)
{
e++;
number /= p;
}
prime.push_back(p);
expon.push_back(e);
}
if (number == 1)
return true;
}
}
return false;
}
void GetDivisors(int n, int count)
{
divisors.push_back(1);
for (int i = 0; i < (int)prime.size(); i++)
{
int p = prime[i];
for (int j = 1; j <= (int)expon[i]; j++)
{
int q = (int)pow(p, j);
divisors.push_back(q);
}
}
bool done = false;
int limit;
do
{
limit = (int)divisors.size();
for (int i = 1; i < limit - 1; i++)
{
int di = divisors[i];
for (int j = i + 1; !done && j < limit; j++)
{
int dj = divisors[j], product = di * dj;
vector<int>::iterator it =
find(divisors.begin(), divisors.end(), product);
if (it == divisors.end())
{
if (divisors.size() < count &&
product <= n && n % product == 0)
divisors.push_back(product);
else if (divisors.size() == count)
done = true;
}
}
}
} while (!done);
std::sort(divisors.begin(), divisors.end());
}
int main()
{
int count = 0, number;
std::cout << "Enter a number = ";
cin >> number;
std::cout << endl;
auto start = chrono::high_resolution_clock::now();
for (int i = 1; i <= number; i++)
{
if (number % i == 0)
{
cout << i << ' ';
count++;
}
}
auto finish = chrono::high_resolution_clock::now();
std::cout << endl << endl;
std::cout << "Divisor count = " << count << endl << endl;
chrono::duration<double> elapsed = finish - start;
std::cout << "Elapsed time = " << elapsed.count()
<< " seconds" << endl << endl;
start = chrono::high_resolution_clock::now();
Sieve();
if (!TrialDivision(number))
{
cout << "Trial division failed!" << endl;
return 0;
}
count = 1;
for (int i = 0; i < (int)expon.size(); i++)
count *= expon[i] + 1;
finish = chrono::high_resolution_clock::now();
std::cout << "Divisor count = " << count << endl << endl;
GetDivisors(number, count);
for (int i = 0; i < (int)divisors.size(); i++)
std::cout << divisors[i] << " ";
std::cout << endl << endl;
elapsed = finish - start;
std::cout << "Elapsed time = " << elapsed.count()
<< " seconds" << endl;
}




I have been playing a jigsaw puzzle app on my Microsoft desktop. The name of the app is “Jigsaw Puzzle HD”. I get one free puzzle per day. I set the number of pieces to 49 which is a 7 by 7 square. It takes me approximately 10 to 20 minutes to solve puzzle. The pieces are large on my Dell display but there is not room to spare using a maximized window and 49 pieces.
Here are some tips I have learned about jigsaw puzzle solving (an algorithm):
I have a nice chess playing app on my desktop computer named “The Chess Lv. 100”. This chess game has 100 levels and Level 1’s Rating is 258 and Level 100’s Rating is 2300. I have a Level 12 Rating of 849 which is probably lower than my United States Chess Federation Rating back in the era 1968 to 1971. I play Level 8 to 12 computer opponents and sometimes venture as high as Level 25 which has a rating of 1094. Here is some information about the United States Chess Federation ratings:
I do not have a simple algorithm for chess, but do not make blunders and try to look several moves into future before you move. Also a good working knowledge of openings, middle-games, and end-games helps.
I modified my battleship Iowa application to use the following input data based on the textbook “Exterior ballistics, 1935” by Ernest Edward Herrmann of the United States Naval Academy:




We get the following data from the Ordnance Pamphlet 770 October 1941
https://eugeneleeslover.com/USN-GUNS-AND-RANGE-TABLES/OP-770-1.html

Sometimes in my group therapy, we play a game of taking an anagram and unscrambling the puzzle and determining all the words that can be created from the unscrambled anagram letters. Suppose we have the scrambled word “cimdteos“ then the following list is created using my new application.
1 demotics
2 domestic
3 ed
4 em
5 me
6 mo
7 om
8 to
9 ti
10 it
11 cs
12 med
13 mot
14 tom
15 tic
16 cit
17 sic
18 sci
19 demo
20 dome
21 mode
22 mote
23 tome
24 omit
25 tics
26 cits
27 stoic
28 sitcom
29 demotic
30 do
31 es
32 st
33 ts
34 mod
35 mes
36 ems
37 est
38 set
39 sit
40 tis
41 its
42 some
43 mets
44 stem
45 ties
46 site
47 domes
48 demos
49 modes
50 motes
51 tomes
52 smote
53 mites
54 emits
55 smite
56 times
57 items
58 cites
59 modest

An anagram is a scrambled or jumbled word. It is a permutation of the letters in a word. There are six permutations of a three letter word such as “the” and are “the”, “teh”, “hte”, “het”, “eth”, and “eht”. The number of permutations of a word consisting of n letters is n!, for example, 4! = 4 * 3 * 2 * 1 = 4 * 3! = 24, 5! = 5 * 4! = 120, etc. I wrote a program to brute force solve anagrams using an English language dictionary consisting of 152,512 words, a hash table, and a permutation generator. The hash table is generated from the English language dictionary by the formula first character integer ASCII value squared + the second character integer ASCII value . The base hash table entry for the word “an” is 65 * 65 + 78 = 4,303. There will be collisions or words with the same hash code. In this case there is a list of words for each hash code value. The application can solve 12 character anagrams in less than one hour on my computer where 12! = 479,001,600. Some anagrams can represent more than one word so a list of potential anagrams is created. Some example executions of the C# application are illustrated below.




I very recently created a multiple precision signed integer package in C++ using the standard library and a base of 10. I then implemented two integer factoring algorithms trial division and Pollard’s Rho method. Trial division uses all the prime numbers <= 10000 and there are 1229 such primes. Due to the choice of language and the exceedingly small base the resulting application is awfully slow when compared to a similar C# application. The multiple precision signed integer package is largely based on translation of the Pascal source code found in “Prime Numbers and Computer Methods for Factorization” by Hans Riesel. The test number is 2 ^ 72 – 1 which is a Mersenne composite integer. The output large integers start with the number of base 10 digits in the number. For comparison I have included the output from my C# Big Integer factorization program as a screen shot. Menu 0 Exit Application 1 Test of Package 2 Trial Division 3 Pollard Rho 2 n = 4722366482869645213695 Duration (min:sec.mil) = 00:08.784 n is composite, factors: 3 ^ 3 factor has 1 digits 5 factor has 1 digits 7 factor has 1 digits 13 factor has 2 digits 17 factor has 2 digits 19 factor has 2 digits 37 factor has 2 digits 73 factor has 2 digits 109 factor has 3 digits 241 factor has 3 digits 433 factor has 3 digits Large prime 5 3 8 7 3 7 Menu 0 Exit Application 1 Test of Package 2 Trial Division 3 Pollard Rho 3 n = 4722366482869645213695 n is composite, factors: 2 2 1 1 3 1 3 4 3 5 1 5 2 1 3 4 1 2 4 1 3 2 4 1 3 1 0 9 3 4 3 3 5 3 8 7 3 7 1 3 1 3 1 3 1 5 1 7 2 1 3 2 1 7 2 1 9 2 3 7 2 7 3 3 1 0 9 3 2 4 1 3 4 3 3 5 3 8 7 3 7 Duration (min:sec.mil) = 00:02.197

I started creating computer programs the Summer Semester of 2002 at Auburn University. I took a course named “Hand Held Software Development”. The course was taught by my research advisor Associate Professor Richard O. Chapman. I created a distributed chess playing client-server Internet system for human chess players. The program was built using the Palm Pilot’s Palm OS and its C language compiler. Later in circa 2006 I built a rule based and neural network chess program for a computer to play itself and for a human observer (voyeur). The language was Java. Then in 2015 I translated and enhanced my Java program by rewriting the code in C#. Below are pictures of one game.






The description of this alphabetic letter game is very facile. Given a word make as many other words as possible using the letters of the given initial word. But first before we enumerate the game solution, we need to refresh the reader’s memory of some elementary mathematics.
The binary number system also known as the base 2 number system is used by computers to perform arithmetic. The digits in the binary number system are 0 and 1. The numbers 0 to 15 in binary using only four binary digits are where ^ is the exponentiation operator (raising a number to a power) are:
0 0000
1 0001 2 ^ 0 = 1
2 0010 2 ^ 1 = 2
3 0011 2 ^ 1 + 2 ^ 0 = 2 + 1 = 3
4 0100 2 ^ 2 = 4
5 0101 2 ^ 2 + 2 ^ 0 = 4 + 1 = 5
6 0110 2 ^ 2 + 2 ^ 1 = 4 + 2 = 6
7 0111 2 ^ 2 + 2 ^ 1 + 2 ^ 0 = 4 + 2 + 1 = 7
8 1000 2 ^ 3 = 8
9 1001 2 ^ 3 + 2 ^ 0 = 8 + 1 = 9
10 1010 2 ^ 3 + 2 ^ 1 = 8 + 2 = 10
11 1011 2 ^ 3 + 2 ^ 1 + 2 ^ 0 = 8 + 2 + 1 = 11
12 1100 2 ^ 3 + 2 ^ 2 = 8 + 4 = 12
13 1101 2 ^ 3 + 2 ^ 2 + 2 ^ 0 = 8 + 4 + 1 = 13
14 1110 2 ^ 3 + 2 ^ 2 + 2 ^ 1 = 8 + 4 + 2 = 14
15 1111 2 ^ 3 + 2 ^ 2 + 2 ^ 1 + 2 ^ 0 = 8 + 4 + 2 + 1 = 15
An algorithm to convert a base 10 (decimal) number to base 2 (binary) number is given below:
Input n a base 10 number
Output b[0], b[1], b[2], … a finite binary string representing the decimal number
Integer i = 0
Do
Integer nmod2 = n mod 2
Integer ndiv2 = n / 2
b[i] = nmod2 + ‘0’
i = i + 1
n = ndiv2
While n > 0
The b[i] will be in reverse order. For example, convert 12 from decimal to using four binary digits:
12 mod 2 = 0
12 div 2 = 6
b[0] = ‘0’
i = 1
n = 6
6 mod 2 = 0
6 div 2 = 3
b[1] = ‘0’
i = 2
n = 3
3 mod 2 = 1
3 div 2 = 1
i = 3
b[2] = ‘1’
n = 1
1 mod 2 = 1
1 div 2 = 0
b[3] = ‘1’
n = 0
So, the reversed binary string of digits is “0011”. And after reversing the string we have 12 is represented by the binary digits “1100”.
Next, we need to define a power set and its binary representation. The index power set of 4 objects which has 2 ^ 4 = 16 entries is specified in the following table:
0 0000
1 0001
2 0010
3 0011
4 0100
5 0101
6 0110
7 0111
8 1000
9 1001
10 1010
11 1011
12 1100
13 1101
14 1110
15 1111
A permutation of the set of three indices is given by the following list:
012, 021, 102, 120, 201, 210
A permutation of n objects is a list of n! = n * (n – 1) * … * 2 * 1. A permutation of 4 objects has a list of 24 – 4-digit indices list since 4! = 4 * 3 * 2 * 1 = 24 has the table:
0123, 0132, 0213, 0231, 0312, 0321,
1023, 1032, 1203, 1230, 1320, 1302,
2013, 2031, 2103, 2130, 2301, 2310,
3012, 3021, 3102, 3120, 3201, 3210
Suppose our word is “lost” then we first find the power set:
1 0001 t
2 0010 s
3 0011 st ts
4 0100 o
5 0101 ot to
6 0110 os so
7 0111 ost ots sot sto tos tso
8 1000 l
9 1001 lt tl
10 1010 ls sl
11 1011 lst lts slt stl tsl tls
12 1100 lo ol
13 1101 lot lto olt otl tlo tol
14 1110 los lso slo sol osl ols
15 1111 lost lots slot etc.
Using a dictionary of 152,512 English words my program finds 16 hits for the letters of “lost”:
Dictionary Length: 152512
Word: lost
0 l
1 lo
2 lost
3 lot
4 lots
5 ls
6 o
7 s
8 slot
9 so
10 sol
11 sot
12 st
13 t
14 to
15 ts
Total letters and/or words 16
Next, we use “tear” as our word:
Dictionary Length: 152512
Word: tear
0 a
1 are
2 art
3 at
4 ate
5 e
6 ea
7 ear
8 eat
9 era
10 et
11 eta
12 r
13 rat
14 rate
15 re
16 rt
17 rte
18 t
19 tar
20 tare
21 tea
22 tear
23 tr
Total letters and/or words 24
Finally, we use the word “company”:
Dictionary Length: 152512
Word: company
0 a
1 ac
2 am
3 amp
4 an
5 any
6 c
7 ca
8 cam
9 camp
10 campy
11 can
12 canopy
13 cap
14 capo
15 capon
16 cay
17 cm
18 co
19 com
20 coma
21 comp
22 company
23 con
24 cony
25 cop
26 copay
27 copy
28 coy
29 cyan
30 m
31 ma
32 mac
33 man
34 many
35 map
36 may
37 mayo
38 mo
39 moan
40 mop
41 mp
42 my
43 myna
44 n
45 nap
46 nay
47 nm
48 no
49 o
50 om
51 on
52 op
53 p
54 pa
55 pan
56 pay
57 pm
58 pony
59 y
60 ya
61 yam
62 yap
63 yo
64 yon
Total letters and/or words 65
The C++ program's source code is given below:
// WordToWords.cpp : This file contains the 'main' function. Program execution begins and ends there.
//
#include "pch.h"
#include <algorithm>
#include <fstream>
#include <iomanip>
#include <iostream>
#include <string>
#include <vector>
using namespace std;
vector<string> dictWords;
bool ReadDictionaryFile()
{
fstream newfile;
newfile.open("C:\\Users\\james\\source\\repos\\WordToWords\\Dictionary.txt", ios::in);
if (newfile.is_open()) {
int index = 0, length = 128;
char cstr[128];
while (newfile.getline(cstr, length)) {
string str;
str.clear();
for (int i = 0; i < (int)strlen(cstr); i++)
str.push_back(cstr[i]);
dictWords.push_back(str);
}
newfile.close();
sort(dictWords.begin(), dictWords.end());
return true;
}
else
return false;
}
string ConvertBase2(char cstr[], int n, int len)
{
int count = 0;
string str, rev;
do
{
int nMod2 = n % 2;
int nDiv2 = n / 2;
str.push_back(nMod2 + '0');
n = nDiv2;
} while (n > 0);
n = str.size();
for (int i = n; i < len; i++)
str.push_back('0');
n = str.size();
for (int i = n - 1; i >= 0; i--)
if (str[i] == '1')
rev.push_back(cstr[i]);
return rev;
}
vector<string> PowerSet(char cstr[], int len)
{
vector<int> index;
vector<string> match;
for (long ps = 0; ps <= pow(2, len); ps++)
{
string str = ConvertBase2(cstr, ps, len);
int psf = 1;
for (int i = 2; i <= len; i++)
psf *= i;
for (int i = 0; i < psf; i++)
{
if (binary_search(dictWords.begin(), dictWords.end(), str))
{
if (!binary_search(match.begin(), match.end(), str))
{
match.push_back(str);
sort(match.begin(), match.end());
}
}
next_permutation(str.begin(), str.end());
}
sort(match.begin(), match.end());
}
return match;
}
int main()
{
bool done = false;
char cstr[128];
int len;
string str;
vector<int> index;
vector<string> match;
if (!ReadDictionaryFile())
return -1;
cout << "Dictionary Length: " << dictWords.size() << endl << endl;
cout << "Word: ";
cin >> cstr;
cout << endl;
len = strlen(cstr);
if (len != 0)
{
vector<string> match = PowerSet(cstr, len);
for (int i = 0; i < match.size(); i++)
{
cout << setprecision(3) << setw(3) << i << "\t";
cout << match[i] << endl;
}
cout << endl;
cout << "Total letters and/or words " << match.size() << endl;
cout << endl;
}
}